z^2-(5+2i)+z+21+i=0

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Solution for z^2-(5+2i)+z+21+i=0 equation:


Simplifying
z2 + -1(5 + 2i) + z + 21 + i = 0
z2 + (5 * -1 + 2i * -1) + z + 21 + i = 0
z2 + (-5 + -2i) + z + 21 + i = 0

Reorder the terms:
-5 + 21 + -2i + i + z + z2 = 0

Combine like terms: -5 + 21 = 16
16 + -2i + i + z + z2 = 0

Combine like terms: -2i + i = -1i
16 + -1i + z + z2 = 0

Solving
16 + -1i + z + z2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-16' to each side of the equation.
16 + -1i + z + -16 + z2 = 0 + -16

Reorder the terms:
16 + -16 + -1i + z + z2 = 0 + -16

Combine like terms: 16 + -16 = 0
0 + -1i + z + z2 = 0 + -16
-1i + z + z2 = 0 + -16

Combine like terms: 0 + -16 = -16
-1i + z + z2 = -16

Add '-1z' to each side of the equation.
-1i + z + -1z + z2 = -16 + -1z

Combine like terms: z + -1z = 0
-1i + 0 + z2 = -16 + -1z
-1i + z2 = -16 + -1z

Add '-1z2' to each side of the equation.
-1i + z2 + -1z2 = -16 + -1z + -1z2

Combine like terms: z2 + -1z2 = 0
-1i + 0 = -16 + -1z + -1z2
-1i = -16 + -1z + -1z2

Divide each side by '-1'.
i = 16 + z + z2

Simplifying
i = 16 + z + z2

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